A machine is sold at a loss of 10%. Had it been sold at a profit of 15%, it would have fetched Rs. 50 more. The cost price of the machine is:

• 200 Rs.
  If cost price=x,then difference in price=115x/100 - 90x/100 =50 so x=200
• 10 years agoHelpfull: Yes(2) No(0)
• 15=(sp1-cp)/cp*100
  sp1=1.15cp
  10=(cp-sp2)/cp*100
  sp2=.9cp
  sp2-sp1=50
  (1.15-0.9)cp=50
  cp=200
• 10 years agoHelpfull: Yes(1) No(0)
• Let us assume cost price of the article is Rs.100x. then selling price = 90x. But if he sold the product for Rs.50 more his profit is 15%. In this case his selling price is 115x. But the difference in the selling prices were gives as Rs.50. So 115x - 90x = 50, therefore x = 2. Substituting in cost price, CP = Rs.200
  
  Alternate method:
  
  Difference in two selling prices = 10% - (-15%) = 10% + 15% = 25% of cost price
  Actual difference in two selling price = Rs. 50 (i.e. 2 times of 25)
  Therefore, Cost Price = 2 x Rs. 100 = Rs. 200
• 10 years agoHelpfull: Yes(0) No(1)