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Maths Puzzle
A three digit non-zero number 'abc' in base 5, when converted to base 7, becomes 'cba'. Which of the following is necessarily true?
option
1. a must be 2
2. c must be 2
3. b must be 0
4. None of these
Read Solution (Total 4)
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- (abc) in base 5 = (cba) in base 7
25a+5b+c= 49c+7b+a
12a-b= 24c
for this equation to satisfy,
for 1st option when a is 2, this will not satisfy the question's condition
but 2nd option satisfy the given condition as follows
when c =2,a=4,b=0 . so no in base 5 is 402, now we covert it into base 7 , it will be equal to 204...So the correct answer is c must be 2 - 11 years agoHelpfull: Yes(3) No(0)
- only 3 statement true
according to question:
25a+5b+c=49c+7b+a
48c+2b-24a=0
it is possible when
b=0 and c=2a
so c may be 2 or 4 and a may be 1 or 2 - 11 years agoHelpfull: Yes(1) No(2)
- 3. b must be 0.
As per given statement
25a+5b+c=49c+7b+a
48c+2b-24a=0
b=12(a-2c)
b can not be more than 4.
so b must be zero only.
a and c can have different values satisfying condition ,a-2c=0 or a=2c
- 11 years agoHelpfull: Yes(1) No(2)
- 1 and 3 must be true..
- 11 years agoHelpfull: Yes(0) No(3)
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