Elitmus
Exam
bhai kisi ne 1 sep ki cryt multiplication ki hai to please share it
Read Solution (Total 3)
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- The question is like that:-
R U Z
M H G
-----------
T A H A
T U Y Z
T H G A
------------------
R A T T T A
and the solution of this question will be
3 4 5
8 7 6
--------------
2 0 7 0
2 4 1 5
2 7 6 0
---------------
3 0 2 2 2 0
Explanation :-
Here it is given that Z*H = Z (where H !=1)
and z*G=A and Z*M=A
this will be happen only if z=5, A=0 , H=3,7,9
and M=2,4,6,8 and G=2,4,6,8
now calculate Z*M and put its values one by one You will get the answer.
if you have any trouble with these type of question please follow this website:-
cryptarithmetic.wordpress.com
and try to solve all the question. - 11 years agoHelpfull: Yes(9) No(0)
- Sorry, Manish i don't have any material for solving cryptarithms. But if you will try to solve cryptarithms problems from these sites i.e. - cryptarithmetic.wordpress.com and file:///D:/study/elitmus/My%20Cryptarithms.htm. you will get lots of method and tricks to solve these problems. Try it. you will get lots of benefits.
- 11 years agoHelpfull: Yes(1) No(0)
- @anmol could you please send some materials for solving
cryptoarithmetic multiplication probblems...my mail is id
manish.pandey806@gmail.com - 11 years agoHelpfull: Yes(0) No(0)
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