120 is the decimal value of a number whose values in base a, b, c are 35 , 80 and 143
then a ,b,c are in ???
a)AP b)GP
c)a,b,c are prime numbers
d)c-b-a=1

• he has posted the question correctly
  problem is there were lot of mistakes in yesterday's elitmus paper.
  around 4 questions were incomplete or there all options were wrong
• 11 years agoHelpfull: Yes(6) No(0)
• a=5, b=8, c=11
  so, it forms A.P.
  ans= a
• 11 years agoHelpfull: Yes(5) No(3)
• Answer: A
  caz 35, 80 r nt prime no's.
  d option also fails.
• 11 years agoHelpfull: Yes(4) No(5)
• I solved it and I got b=15 and c=9..but i am not able to find out the value of a....from b=15 and c=9 options c and d already eliminated...
  If this question is wrong posted then plz let me know about right one.
  Thanks...
• 11 years agoHelpfull: Yes(4) No(2)
• on solving,we get
  a=35,b=15 and c=9
  so,i think none of the option is correct or the option provided is wrong.
• 11 years agoHelpfull: Yes(2) No(1)
• u have posted wrong question.....
• 11 years agoHelpfull: Yes(1) No(4)
• on solving we get a=115/3,b=15,c=9
  there is no option
  I think question is wrong
• 11 years agoHelpfull: Yes(1) No(0)
• questin is wrong???? please correct it--- refer to uploader
• 11 years agoHelpfull: Yes(0) No(3)
• 35 in base a = its decimal equivalent given-120
  =>3*a^1 + 5*a^0 = 120
  =>a = 115/3
  
  similarly,
  8*b^1 + 0*b^0 = 120
  =>b = 15
  
  and 1*c^2 + 4*c^1 + 3*c^0 = 120
  => c = 9 or -13
  
  therefore, a=115/3,b=15,c=9 or -13
  So none of the obtions are correct
• 11 years agoHelpfull: Yes(0) No(0)
• 1*a^2+2*a^1+0*a^0=35 ->> a^2+2a=35 ->> a=5
  
  1*b^2+2*b^1+0*b^0=80 ->> b^2+2b=80 ->> b=8
  
  1*c^2+2*c^1+0*c^0=143 ->> c^2+2c=143 ->> c=11
  
  so a=5, b=8, c=11 Hence in A.P
• 11 years agoHelpfull: Yes(0) No(1)