In a family of five person A,B,C,D and E every one loves one another. there birthdays are in different month and on diff dates . A bday is between 25th and 30th, B is betwn 20th and 25th,C is betwn 10th and 20th, D is betwn 5th and 10th and E is betwn 1st to 5th of the month.the sum of the of birth is definrd as the addition of date and month,for example 12th jan will be written as 12/1 and will add to a sum of the date of 13.(between 25th and 30th includes both 25 and 30). What may be the max average of their sum of the dates of birth ?

• Here may be different combinations of date of birth.
  As per question, to find max average of their sum of DOB,we can't take starting months
  we have combinations
  30/8,25/9,20/10,10/11,5/12
  here average = (38+34+30+21+17)/5 =140/5 = 28
  30/8,25/12,20/11,5/9,10/10
  Avg = 28
  30/11,25/12,20/810/9,5/10
  Avg = 28
  30/12,25/11,20/10,10/9,5/8
  Avg = 27.6
  So maximum average of sum of their Dob = 28 Ans
• 11 years agoHelpfull: Yes(20) No(0)
• moths will defer => we have to take maximum value of their sum of DOB => so takes dates and moth max possible as shown below:
  range date month
  25- 30(A) 30 12
  20-25(B) 25 11
  10-20(C) 20 10
  5-10(D) 10 9
  1-5(E) 5 8
  
  now take the sum (30+12)+(25+11)+(20+10)+(10+9)+(5+8) / 5 = 28 (ans)
• 11 years agoHelpfull: Yes(6) No(2)
• for max avg if we take,
  30/12,25/11,20/10,10/9,5/8,1/7 then avg is 37.6
• 11 years agoHelpfull: Yes(2) No(5)
• given,
  25
• 11 years agoHelpfull: Yes(0) No(8)