four cards are drawn from a pack of 52 cards one by one without replacement. what is the probability that each card is of different suit and different domination

• no condition for drawing 1st card.
  suppose drawn card is 7 of spade. the 2nd card drawn must not be either spade or 7.
  
  favorable space = (52)-(13 cards of spade)-(3 cards of denomination "7") =36
  total no of space =51
  P2= 36/51
  
  same way for 3rd card drawn-
  favorable = 36-(14) =22
  total =50
  p3=22/50
  
  for last card-
  p4=10/49
  
  reqd probability =(52*36*22*10)/(52*51*50*49)
• 10 years agoHelpfull: Yes(15) No(0)
• suppose if you draw card '7 of spade' in 1st draw,in the 2nd draw all spades will be excluded and 7 of diamonds,hearts,club will also be excluded,so you will have only 36 cards to choose from 51.
  Next draws will follow the same logic.
  required ans = (52 x 36 x 22 x 10) / (52 x 51 x 50 x 49)
• 10 years agoHelpfull: Yes(9) No(2)
• 1st card is taken from 52 cards=52/52 (of one suit and one domination)
  2nd card is taken from 51 cards=36/51 (of 2nd suit and other domination)
  3rd card is taken from 50 cards=24/50 (of 3rd suit and other domination)
  4th card is taken from 49 cards=12/49 (of 4th suit and other domination)
  so answer is (52*36*24*12)/(52*51*50*49)
• 10 years agoHelpfull: Yes(2) No(0)
• 1st card is selected from 52 cards, I don't care what will be P1=1
  for 2nd card p2=3/51
  for 3rd card p3=2/50
  for 4th card p4=1/49
  so for all 4 cards the answer will be 1*(3/51)*(2/50)*(1/49) = 6/(51*50*49)
• 10 years agoHelpfull: Yes(1) No(8)
• there are 4 suits of 13 each.. one card is drawn from each so 4*13c1/52c4
• 10 years agoHelpfull: Yes(1) No(2)
• 1st card is taken from 52 cards=52/52 (of one suit and one domination)
  2nd card is taken from 51 cards=38/51 (of 2nd suit and other domination)
  3rd card is taken from 50 cards=24/50 (of 3rd suit and other domination)
  4th card is taken from 49 cards=10/49 (of 4th suit and other domination)
  so answer is (52*38*24*10)/(52*51*50*49)
• 10 years agoHelpfull: Yes(0) No(3)
• 1st card is taken from 52 cards=52/52 (of one suit and one domination)
  2nd card is taken from 51 cards=36/51 (of 2nd suit and other domination)
  3rd card is taken from 50 cards=22/50 (of 3rd suit and other domination)
  4th card is taken from 49 cards=10/49 (of 4th suit and other domination)
  so answer is (52*36*22*10)/(52*51*50*49)
• 10 years agoHelpfull: Yes(0) No(1)
• (13C1)^4/52C4
• 10 years agoHelpfull: Yes(0) No(2)