self
Maths Puzzle
The square of a two digit number is divided by half the number. After 36 is added to the quotient, this sum is then divided by 2. The digits of the resulting number are the same as those in the original number, but they are in reverse order. The ten's place of the original number is equal to twice the difference between its digits. What is the number?
Read Solution (Total 1)
-
- let the digits be x and y. then the number is 10x+y
given: (10x+y)^2/[(10x+y)/2]=2(10x+y).
[2(10x+y)+36]/2=10y+x
or, 10x+y+18=10y+x
or, 9y=9x+18
or, y=x+2
therefore, 10x+y=13,24,35,46,57,68,79
hence there are 7 such two digit numbers - 11 years agoHelpfull: Yes(3) No(2)
self Other Question