A car travels from B at a speed of 20 km/hr. The bus travel starts from A at a time of 6 A.M. There is a bus for every half an hour interval. The car starts at 12 noon. Each bus travels at a speed of 25 km/hr. Distance between A and B is 100 km. During its journey ,The number of buses that the car encounter is ?

• Betweem 6 am to 12pm ,12 buses are released from A (2*6=12 ,as per hour 2 buses are released).
  Now the bus starting at 6am reaches B at 10am ,since time taken by bus to travel 100km is(100/25=4 hrs).Similarly,bus starting at 6.30am would reach B at 10.30am and so on..By the time it's 12pm the bus starting at 8am would have reached B.In this process a total of 5 buses had already arrived to B by 12pm.So,remaining(12-5),i.e,7 buses are on their way to B and will meet the car along the way.Now the car starting at 12pm takes(100/20=5 hrs) to reach A.Within this 5 hours (5*2) i.e.,10 more buses are released which will also meet Car on it's way.So ,we have(7+10)=17 buses meeting car on it's way.
  :-)
  
• 12 years agoHelpfull: Yes(27) No(0)
• Total journey = 100 km.
  The bus travel starts from A at a time of 6 A.M. and each bus travels at a speed of 25 km/hr so time required for the bus to complete the journey = 4 hrs.
  so the bus starts at 8:30 will meet with the car moving in opposite direction definitely.
  Car travels from B at a speed of 20 km/hr so time of arrival of car at A is 5 P.M., it means the last bus which will meet with the car is that starts at 4:30 P.M.
  so total bus ranges from 8:30 P.M. to 4:30 P.M. = 17
• 13 years agoHelpfull: Yes(17) No(0)
• ans- 5 buses
  EXPLANATION-
  first we have to find time to cover distance 100km by bus & it will be 100/24=4 hrs.
  it means first bus will reach point B at 10am
  second....................................10:30
  3..........................................11:00
  4..........................................11:30
  5...........................................12:00pm
  5th bus will also encounter the bus because of greater speed.....
• 13 years agoHelpfull: Yes(3) No(15)
• This is the "Frog in the Well" problem.
  
  The question is: "How long does it take a car to move 250 cm forward?"
  
  
  We can baby-step through the solution.
  
  Draw a number line for reference.
  
  In 2 seconds, it moves 100 cm forward.
  In the next 2 seconds, it moves 50 cm back.
  It is at "50".
  . . In 4 seconds, it moved 50 cm forward.
  
  In the next 4 seconds, it moves 50 cm forward.
  . . It is at "100".
  
  In the next 4 seconds, it moves 50 cm forward.
  . . It is at "150".
  
  In the next 2 seconds, it move 100 cm forward.
  . . It is at "250".
  
  
  Therefore, they will collide in 14 seconds.
  
• 13 years agoHelpfull: Yes(1) No(12)
• As we need to know the counter of the bus and car..we should take with respective to the car..The car makes one journey only but bus can make many journeys.
  so From 12pm to 5 pm they meet for every 30 min..Ans=>11
• 13 years agoHelpfull: Yes(1) No(5)
• 19 buses. when car starts at 12:00 it comes accross the bus of 8:00, From this moment until it reaches to its destination at 17:00 (including the 17:00 bus), there are 19 buses around.
• 12 years agoHelpfull: Yes(1) No(5)
• Betweem 6 am to 12pm ,12 buses are released from A (2*6=12 ,as per hour 2 buses are released).
  Now the bus starting at 6am reaches B at 10am ,since time taken by bus to travel 100km is(100/25=4 hrs).Similarly,bus starting at 6.30am would reach B at 10.30am and so on..By the time it's 12pm the bus starting at 8am would have reached B.In this process a total of 5 buses had already arrived to B by 12pm.So,remaining(12-5),i.e,7 buses are on their way to B and will meet the car along the way.Now the car starting at 12pm takes(100/20=5 hrs) to reach A.Within this 5 hours (5*2) i.e.,10 more buses are released which will also meet Car on it's way.So ,we have(7+10)=17 buses meeting car on it's way
  
• 9 years agoHelpfull: Yes(1) No(0)
• it shud be 11
• 13 years agoHelpfull: Yes(0) No(7)
• ans shud be 15
• 10 years agoHelpfull: Yes(0) No(5)