two years before paul's age was 6 times the alice age and than present age of paul is 2 times than alice's .what is present age of paul.

• let paul's age be P and alice be A
  before 2 years paul's age (P-2) and alice age (A-2)..
  (P-2)=6(A-2) => P-2=6A-12 => 6A-P=10
  and presently P=2A => A=P/2
  6(P/2)-P=10
  3P-P=10
  2P=10
  P=5
• 10 years agoHelpfull: Yes(12) No(0)
• let present ages are, x & y
  therefore, x=2y
  & (x-2)=6(y-2)
  solving the upper two eqsn. we get x=5,y=5/2
• 10 years agoHelpfull: Yes(0) No(1)
• Ans:5 years
  let alice age be x for 2 years ago then paul's age will 6x.
  Their present ages are x+2,6x+2.Then 6x+2=2(x+2)
  x=1/2.Then paul's present age is 6(1/2)+2=5.
• 10 years agoHelpfull: Yes(0) No(0)
• Let alice age be X and Pauls be Y
  resent age of paul is 2 times than alice's ==> Y=2X
  two years before paul's age was 6 times the alice age ==> Y-2=6(X-2)
  2X-2=6X-12
  4X=10 ==>X=2.5
  Paul's age is 2.5*2=5
  
• 10 years agoHelpfull: Yes(0) No(0)