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two years before paul's age was 6 times the alice age and than present age of paul is 2 times than alice's .what is present age of paul.
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- let paul's age be P and alice be A
before 2 years paul's age (P-2) and alice age (A-2)..
(P-2)=6(A-2) => P-2=6A-12 => 6A-P=10
and presently P=2A => A=P/2
6(P/2)-P=10
3P-P=10
2P=10
P=5 - 11 years agoHelpfull: Yes(12) No(0)
- let present ages are, x & y
therefore, x=2y
& (x-2)=6(y-2)
solving the upper two eqsn. we get x=5,y=5/2 - 11 years agoHelpfull: Yes(0) No(1)
- Ans:5 years
let alice age be x for 2 years ago then paul's age will 6x.
Their present ages are x+2,6x+2.Then 6x+2=2(x+2)
x=1/2.Then paul's present age is 6(1/2)+2=5. - 11 years agoHelpfull: Yes(0) No(0)
- Let alice age be X and Pauls be Y
resent age of paul is 2 times than alice's ==> Y=2X
two years before paul's age was 6 times the alice age ==> Y-2=6(X-2)
2X-2=6X-12
4X=10 ==>X=2.5
Paul's age is 2.5*2=5
- 11 years agoHelpfull: Yes(0) No(0)
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