A team won 80% of the games it played. It played 5 more games of which it won 3 and lost 2. Its loss percentage changed to 25%. How many games did it play overall?
A. 20
B. 14
C. 16
D. 25

• ans= 20
  if game played=x
  then lost game=x/5
  now they played 5 more games in which they lost 2
  so, (x+5)*25/100=x/5 + 2
  x=15
  so total game he played=15+5 = 20
• 10 years agoHelpfull: Yes(59) No(13)
• ans= 20
  if total game played=x
  then lost game=x/5
  now they played 5 more games in which they lost 2
  so, (10+x)/5*(x+5)=25%
  x=15
  so total game he played=15+5+20
• 10 years agoHelpfull: Yes(14) No(6)
• we can also do this problem like this..
  let us consider they have played 10 games out of which they won 8 games
  next they have played 5 more games out of which they won 3 games and lost 2so now they have lost 4 games
  by hit and trail if the answer is 20 games then 16%of20 means 4 games ie this is the only option which shows they have lost 4 games
  so the ans is 20
• 9 years agoHelpfull: Yes(12) No(2)
• let the total no of games played by the team be 10
  
  team wins 80% of the game it played --> 10*(80/100)= 8
  
  so the team has won 8 games and lost 2
  
  it is given that 5 more games are played
  
  which implies, 10+5=15
  
  and also given that it lost 2 and won 3 ( in tat 5 games)
  
  so total number of games won is 8+3=11
  
  total number of games lost = 4
  
  hence total number of games played = 15
  
  here loss percentage (25 % ) is given to confuse
  
  ANSWER: 15
  
  
  
• 8 years agoHelpfull: Yes(4) No(10)
• ans is 20..
• 10 years agoHelpfull: Yes(3) No(4)
• 20 20
• 10 years agoHelpfull: Yes(1) No(4)
• Initially 80% win percentage and 20% loss percentage,
  after playing 5 game, 75% win percentage and 25% loss percentage.
  i.e. 80%-75%=3/5 (as out of 5 games 3 games are won)
  =>5% = 3/5
  =>100% = 3/25*100=12
  
  similarly, 25% - 20% = 2/5 (as 2 out of 5 games are lost)
  => 5% = 2/5
  =>100% = 2/25*100=8
  
  hence, total match played =12+8 = 20
• 2 years agoHelpfull: Yes(1) No(0)
• Let total number of games initially played be n
  Team won 80% of the games => Lost games = 20% of n = n5n5
  After that they played 5 more games in which they lost 2
  Now their loss
  (n+5) ×25100×25100 = n5n5 + 2
  n=15
  Therefore total games the team played=15+5 = 20
  
• 7 years agoHelpfull: Yes(0) No(0)
• IF TOTAL GAMES =T
  T-5 80% WON
  80% WON
  LET Y=5 GAMES PLAYED
  3 WON MEANS 60% WON
  COMBINELY WE HAVE 25% LOSS MEANS 75% GAIN SO
  
  (T-Y)80+(5*60)=T*75
  T=20
• 5 years agoHelpfull: Yes(0) No(0)
• Assume they played x games before the match.
  
  As there win %age is 80 they won 0.8x games and lost the rest i.e. 0.2x games.
  
  After playing 5 more games they lost 2 and there loss %age became 25%.
  
  This can be written as,
  
  Total lost gamesTotal games played⋅100=25
  0.2x+2x+5=.25
  x=15
  So they played 20 games in total.
• 5 years agoHelpfull: Yes(0) No(0)
• ans=20
  total loss%=[(total loss)/total games]*100
  total loss%=25
  totl loss=20% of x+2
  total games=x+5
  solving that we get x=15 and total game=x+5
  so 15+5=20ans
• 4 years agoHelpfull: Yes(0) No(0)