Arun makes a popular brand of ice-cream in a rectangular shaped bar 6 cm long, 5 cm wide and 2 cm thick. To cut costs, the company had decided to reduce the volume of the bar by 19%. The thickness will remain the same, but the length and width will be decreased by the same percentage. The new width will be

• volume v=l*b*t
  new volume is 81% of old v.
  therefore new vol = 81%(v)=l'*b'*t
  => 81% (l*b*t) = l'*b'*t
  => 81% (l*b) = l' * b'
  since the change in new l and b is the same. hence consider change to be x.
  => 81% (l*b) = xl*xb
  81%=x^2
  x=9%.
  9% change in 5cm width is 0.45
  therefore new width is 5-0.45=4.55cm
• 11 years agoHelpfull: Yes(33) No(4)
• let d width decrease by 10% and length by 10% too..
  den total volume degradation will be as thickness is same..
  -10 -10 +10*10/100=-19%
  thus new width will be 0.9*5 = 4.5cm
  
• 11 years agoHelpfull: Yes(11) No(4)
• since volume decrease by 19%
  so,new vol=60-(60*19)/100=48.6
  let length decrease by x%
  so,now(6-6x/100)*(5-5x/100)*2=48.6
  solving this we get two values of x i.e. x=190,10
  so,190 can not be solution so reduired is 10%.
  so,new width is 5-5*10/100=4.5.
  4.5 is the new width.
• 11 years agoHelpfull: Yes(10) No(1)
• 4.05 cm is the ans
• 11 years agoHelpfull: Yes(7) No(5)
• Volume =l×b×h = 6×5×2 = 60 cm3
  Now volume is reduced by 19%.
  Therefore, new volume = (100−19)100×60=48.6
  Now, thickness remains same and let length and breadth be reduced to x%
  so, new volume: (x100×6)(x100×5)2=48.6
  Solving we get x =90
  thus length and width is reduced by 10%
  New width = 5-(10% of 5)=4.5
• 10 years agoHelpfull: Yes(6) No(1)
• v=60
  new vol=48.6
  48.6=l*b*w=x^2*2
  x^2=24.3
  x=4.92
• 11 years agoHelpfull: Yes(5) No(23)
• but answer is 8.1cm
• 8 years agoHelpfull: Yes(0) No(1)
• initial volume =5*4*3=60
  now let w and l is decreased by x% where thickness remains same(2cm)
  then
  2 * (100-x)%of w * (100-x)%of l=81% of 60
  2*(100-x)^2/100 *5*6=(81/100)*60
  x=91%
  hence
  new width is 91%of 5
  = 4.55
• 6 years agoHelpfull: Yes(0) No(0)