A can finish a JOB in 24 days and M in 36 days. A,M and H together can finish in 8 days. H alone can do in how many days?

• A = 1/24
  B = 1/36
  A+M+H = 1/8
  
  then
  
  H = 1/8 - {1/24 + 1/36}
  => 1/8 - {3/72 + 2/72}
  => 1/8 - 5/72 => 9/72 - 5/72
  =>4/72 => 1/18 => 18 days
• 11 years agoHelpfull: Yes(18) No(0)
• let total unit of job 72 unit.A can do in 1 day 3 unit.B 2 unit.remaining 9-5=4 unit.h can do 72/4=18 days.
• 11 years agoHelpfull: Yes(1) No(1)
• 1/A + 1/M + 1/H = 1/8
  Put A = 24, M = 36
  H = 18
• 11 years agoHelpfull: Yes(1) No(0)
• we have work done by A=24 days,b=36 days.
  so work done in 1 day by A=1/24 AND b=1/36
  LET work done by H in 1 day=1/x
  then, total work done by all three in 1 day=1/24+1/36+1/x=1/8
  on solving,x=18 days
• 11 years agoHelpfull: Yes(0) No(0)
• 18 864/48
• 11 years agoHelpfull: Yes(0) No(0)
• take lcm of 24 and 36 that is 72
  so a does 3 unit and m does 2 unit
  given (3+2+x)*8=72
  5+x=9
  x=4
  so h do 4 unit per day
  so he ll take
  72/4=18 days
  
• 11 years agoHelpfull: Yes(0) No(0)