76 345 23 245 find last digit no ans should be with explain

76^345 * 23^245
for 76^345
Unit Digit of 76^345 = 6

for 23^245
=(23^4)^61 * 23
Unit digit of (23^4)^61 =1
and Unit digit of 23 = 3
so Last digit of whole = 6*1*3 =18 =8
Answer = 8
11 years agoHelpfull: Yes(0) No(0)
345/4,remainder=1then we have unit digit 6^1=6
and 245/4,remainder=1,then we have unit digit 3^1=3
and finally 6*3=18,so unit digit is 8
11 years agoHelpfull: Yes(0) No(1)
yes ans is 8
11 years agoHelpfull: Yes(0) No(0)
76^345=last digit(6);
23^245=last digit(3);
as we can see
23^1=23
23^2=529
23^3=12167
23^4=279841
23^5=6436343
that means after every 5 time we get last digit of23 will be 3 so (6*3)=18 so last digit will be 8.
11 years agoHelpfull: Yes(0) No(0)
hii nisha
plz elaborate dis solution ..
i couldn't understand your logic...
11 years agoHelpfull: Yes(0) No(0)

76^345 * 23^245=?
find last digit no.?
ans should be with explain..