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Numerical Ability
Permutation and Combination
A man has 3 shirts, 4 pairs of trousers and 6 ties. What are the number of ways in which he can dress himself with a combination of all the three?
A. 72
B. 13 ! / ( 2 ! * 4 ! * 6 !)
C. 3 ! * 4 ! * 6 !
D. 13
Read Solution (Total 9)
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- 3c1 * 4c1 *6c1 = 3*4*6 =72
- 11 years agoHelpfull: Yes(28) No(0)
- ans : 72
@admin please solve this question.. this type of questions always create confusions. - 11 years agoHelpfull: Yes(4) No(2)
- total combination will be---
3c1*4c1*6c1=72 - 11 years agoHelpfull: Yes(2) No(0)
- wearing 1 out of 3,4 or 6 things gives 3,4 and 6 ways respectively now when we look at combination of all we need to multiply them so we have
3c1*4c1*6c1=72 - 11 years agoHelpfull: Yes(1) No(0)
- it will be 3C1*4C1*C1=72
- 11 years agoHelpfull: Yes(1) No(0)
- If we have three shirts then wear the shirts in 3! ways so I thin answer is
3!*4!*6! - 11 years agoHelpfull: Yes(0) No(4)
- By hit and trial......starting from 27 (21(multiple of 7)+ 6 as remainder)and traversing 34,41,28,...69,76 gives the valid answer.. :)
- 11 years agoHelpfull: Yes(0) No(0)
- 3c1*4c1*6c1=72 ways
- 11 years agoHelpfull: Yes(0) No(0)
- Answer is 72.
Soln:
With 3 shirts, we have 4 pants, total combination is 3*4=12.
With 12 combinations of shirt and pant, we have 6 ties, total combination= 12*6 = 72 - 5 years agoHelpfull: Yes(0) No(0)
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