the video size is 68.7mb,the downloadable speed is 0.1mb/sec, what is the exact time required to download this video

• 11 minutes 27 seconds. (687 seconds)
• 13 years agoHelpfull: Yes(3) No(0)
• just divide 68.7 by 0.1,so the answer will be=(68.7/0.1)sec=687 sec=11 min. 27 sec
• 13 years agoHelpfull: Yes(1) No(0)
• totalsize/speed;
  68.7/0.1 = 687 seconds
• 13 years agoHelpfull: Yes(0) No(0)
• look dear friend,
  one Byte = 8 bits
  the internet speed is always calculated in bits. so when your internet speed is 512Kb, it means that your download speed is 64KB max. with 64KBs you can download one MegaByte in 15.625 seconds.
  
  so the ans will be 68.7*8/0.1=5496 seconds
  
• 13 years agoHelpfull: Yes(0) No(1)
• it vl require 687 seconds
  as 0.1 req 1 sec
  so 68.7 req ?
• 13 years agoHelpfull: Yes(0) No(1)
• time required=68.7/0.1=687 seconds=11 minutes and 27 seconds..
• 13 years agoHelpfull: Yes(0) No(0)