The sum of the squares of three numbers is 532 and the ratio of the first to the second as

let the no be a, b, c
A/Q a:b=3:2----(1)
b:c=3:2----(2)
multiply (1) & (2)
we get a:c= 9:4
.'. a:b:c = 9:6:4 =x { a=9x, b=6x & c=4x}
A/Q (a^2)+(b^2)+(c^2)=532
x^2[81+36+16]=532
x=2
so b= 6*x = 12
2nd no is 12
11 years agoHelpfull: Yes(4) No(0)
nos are in the ratio 9:6:4 by hit and trial we get take the nos as 18:12:8
now 18^2 + 12^2 + 8^2 gives 532 so the nos is 12
11 years agoHelpfull: Yes(2) No(0)
x^2+y^2+z^2=532........(1)
x/y=3/2 => x=(3y)/2.....(2)
y/z=3/2 => z=(2y)/3.....(3)
Putting (2)&(3) in (1) and after solving
we get y=12(Ans)
11 years agoHelpfull: Yes(1) No(0)
given a^2+b^2+c^2= 532..............(1)
a/c to question a/b=3/2.
thus a=3b/2........(2)
and given b/c= 3/2.
thus c=2b/3.............(3)
put the value of a and c in eqn (1),we get
b=12......ans
11 years agoHelpfull: Yes(1) No(1)
The problem is pretty simple..
lets the numbers be x,y,z
x y z
3 2 (2)
(3) 2 2
------------------
9 : 4 : 2

therefore x:y:z=9:4:2
so as per given condition.
x^2+y^2+z^2=532
(9x)^2+(4y)^2+(2z)^2=532
x^2=4
x=2
therefor middle number is 6*2=12
8 years agoHelpfull: Yes(0) No(0)

The sum of the squares of three numbers is 532 and the ratio of the first to the second as also of the second to the third is 3:2. What is the second number?