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Maths Puzzle
A number when divided by 10, 13 and 16 gives remainders 2, 4 and 6 respectively. Find the least such number possible.
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- let the number be x.
X gives remainder 2,4 and 6.
3x/2 will give remainders 3, 6 and 9.
possible values of 3x/2 = 1033, 2073
possible value of x = 2073*2/3 = 1382
smallest possible value of x = 1382 - lcm = 1382-1040 = 342
Source of problem : C4 Training Company
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