T & e r 90 kms apart.dey start moving towards each oder.T at a speed of 10 kmh and e at 5 kmh.In evry 1 hr dey double der speed.wat distance tim covered wen dey met?

• in the 1st hour total distance covered is(10+5)=15km
  in the next hour the distance covered is=(20+10)=30km..
  total dis covered in two hour is=(15+30)=45km...
  left=(90-45)=45km..
  to cover this distance time taken 45/60=3/4hr..
  total distance covered by tim is=(10+20+40*3/4)=60km...
  s
• 10 years agoHelpfull: Yes(10) No(3)
• 30 kms
  after 2 hrs, distance bw them is 45 kms
  let tim cover x kms wen they meet
  x/40 = (45-x)/20=> x=30
• 10 years agoHelpfull: Yes(2) No(3)
• 60 km is the ans
• 10 years agoHelpfull: Yes(1) No(2)
• 1hr 1hr 1/2hr 1/4hr 1/4hr 1/2hr 1hr 1hr
  T|-----|-----|-----|-----|(Meeting point)|-----|-----|-----|-----|E
  10km 20km 20km 10km 5km 10km 10km 5km
  
  T to Meeting point distance = 60kms
• 10 years agoHelpfull: Yes(1) No(0)
• yes total= 30+ dist covered in first two hrs=60
• 10 years agoHelpfull: Yes(0) No(2)
• quetion is confusing but both are double their speed but distance is same
  so meeting point of t and r is after 6hr
  and speed of t is 10kmh
  therefore
  distance= s*t = 6*10=60km
• 10 years agoHelpfull: Yes(0) No(0)