like from height of 8 mts on ball fell down and each time it bounces half the distance back. so what will be the distance travelled

• 24
  
  The distance travelled will be
  
  8+(4+4)+(2+2)+(1+1)+.5+.5+.25+.25+....
  or
  8+8+4+2+1+0.5 ... up to infinity
  or
  8+(8+4+2+1+0.5 ... up to infinity)
  
  Now (8+4+2+1+0.5 ... up to infinity) is a GP with a=8 and r=1/2=0.5.
  sum of GP = a/(1-r) = 8/(1-0.5) = 8/0.5 =16
  
  hence 8+(8+4+2+1+0.5 ... up to infinity) = 8+16 =24
• 13 years agoHelpfull: Yes(34) No(1)
• 24 mts
  8+4+4+2+2+1+1+....... = 24
• 13 years agoHelpfull: Yes(10) No(3)
• 24
  as 8+4+4+2+2+1+1+.5..... infinit
  sumation is 8 + GP of ( 8+4+2+1.......infinity)
  8+ 8/.5
  8+16 = 24
  
• 13 years agoHelpfull: Yes(4) No(3)
• suppose the ball falls from a height of x m
  then next time it bounces to a height of x/2 and then falls althrough x/2 height and again bounces back to x/4 height and continues till it comes to rest.
  so total distance travelled = x+2(x/2)+2(x/4)+2(x/8).......
  =x(1+1+1/2 +1/2^2+....)
  =x(1+2)=3x (because 1+1/2+1/4+1/8+... forms an infinite gp whose r
• 13 years agoHelpfull: Yes(1) No(6)
• each time ball is travelling the half of the previous one, so sequence is 8,4,2,1,.5,......
  it is infinite GP series so
  d=8/(1-1/2)=16
• 11 years agoHelpfull: Yes(1) No(8)