P finishes 6/7th of the work in 2x hours, Q works twice as fast and finishes the remaining work. For how long did Q work?

• x/6 hours
  P can complete whole work alone in 2x/(6/7)=7x/3 hours
  As Q is twice as fast as P,so can complete whole work in 7x/6 hours
  Work remaining after P has done 6/7 work =1/7
  So time taken by Q to complete the remaining work=(1/7)(7x/6)= x/6 hours
  
• 11 years agoHelpfull: Yes(0) No(0)