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Given series 1, 6, 7, 13,.....
Calculate the sum of first 52 terms...???
Read Solution (Total 5)
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- we can take this series as 1,7,..........
&6,13,.............
so for first part sum will be=[26/2*(2+(25*6))]=1976
so for second part sum will be=[26/2*(12+(25*7)]=2431
so some will be (1976+2431)=4407. - 11 years agoHelpfull: Yes(8) No(18)
- sum=n/2(a+l) where n=number of terms..and a=first term..and l=last term..
let the commmon difference be d. then 52th term=a+51d=1+51*6=307
so sum=52/2(1+307)=8008 - 11 years agoHelpfull: Yes(2) No(12)
- @kapil dev kumar
this series is not in AP - 11 years agoHelpfull: Yes(1) No(1)
- plz send d solution....
- 11 years agoHelpfull: Yes(0) No(1)
- fibonacci series!! how 2 solve :(
- 11 years agoHelpfull: Yes(0) No(0)
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