Ram singh goes to pushkare melars 300 and with rs 10000 to buy exactly 100 animals.he find that cow are sold at rs 1000,horses at rs 300 and chicken at rs 50.how much chicken should be buying to meet his target of 100 animals.

92
94
90
88

• let there be x cows,y horses and z chicken....
  x+y+z=100
  1000x+300y+50z=10000
  now,consider the options:
  let z=92
  50*92=4600
  left=5400 which cant satisfy the eqns. for any integer x nd y...
  now,let z=94
  50*94=4700
  left=5300 which satisfy the eqns for x=5 nd y=1..
  therefore ans=(b)
• 11 years agoHelpfull: Yes(12) No(1)
• He should buy 94 chickens
  94 chickens will cost him Rs4700
  Amount remaining=Rs 5300 by which he can buy 1 HORSE(Rs.300) and 5 COWS(Rs.500
  94+1+5=100(animals).
• 11 years agoHelpfull: Yes(7) No(2)
• optional verification should be done
• 11 years agoHelpfull: Yes(1) No(0)
• (94*50)+(5*1000)+(300*1)=10000..
  as we get from above number of chicken=94
  number of horse=1
  number of cow=1000
• 11 years agoHelpfull: Yes(0) No(0)
• the ans is 94
  because if we multiply 94 with 50 we get 4700
  so this amount is somepart, which is possible to
  make a digit 10000
  i.e
  4700+300+5000
  so possibility is 94
  where the remaining options were not suitable
• 11 years agoHelpfull: Yes(0) No(0)