(753*753+247*247-753*247)/753*753*753+247*247*247=?
option
a) 1/1000
b) 1/506
c) 253/500
d) none of these

• let a=753
  b=247
  the question reduces to=> (a^2+b^2-ab)/(a^3+b^3)
  factoring the denominator=>
  (a^2+b^2-ab)/[(a+b)(a^2+b^2-ab)]
  => 1/(a+b)
  => 1/(753+247)
  => 1/1000
• 11 years agoHelpfull: Yes(23) No(0)
• ans: 1/1000
  let a=753 & b=247
  now the given expression becomes,
  (a^2+b^2-ab)/(a^3+b^3)
  now we know,
  a^3+b^3=(a+b)*(a^2+b^2-ab)
  now,
  (a^2+b^2-ab)/(a^3+b^3)=1/(a+b)
  =1/(753+247)=1/1000
  
• 11 years agoHelpfull: Yes(3) No(0)
• 1/a-b=1/506
• 11 years agoHelpfull: Yes(0) No(7)