RAM GOES A TO B . IF HE TAKES 1/4 TIME LESS THAN TO COVER THE SAME DISTANCE WHEN RUN AT NORMAL SPEED BY WHAT % HE HAS INCREASED HIS SPEED ?

• let distance =x
  and time=t
  s=x/t
  when he run at speed
  t'=t-1/4t
  t'=3/4t
  distance remain same
  s*t=s'*3/4t
  s'=4/3s
  %increase in speed=33.3%
  
  
• 11 years agoHelpfull: Yes(35) No(5)
• Let v1=t1=100,
  now t2= 75(1/4*100)
  v1*t1=v2*t2
  100*100=v2*75 now v2 =133.33, that is 33. 33% more
  
  
  
  
• 11 years agoHelpfull: Yes(6) No(2)
• Normal Time =1
  increase change time=1/4
  
  1-1/4 =3/4
  
  but time is inversely proportional to speed
  so=4/3 =33.3
  
• 10 years agoHelpfull: Yes(5) No(0)
• ans is 400%
• 11 years agoHelpfull: Yes(1) No(24)