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Numerical Ability
Averages
Person travels to a hill, if he goes from A to B with speed of 4kmph and returns back to B with speed of 5kmph. What is his average speed of journey?
Read Solution (Total 4)
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- Let the distance one way be X km
Time taken to go up = X /4 hours
Time taken to come down = X /5 hours
Total time -= X / 4 + X / 5 = 9X/ 20 HOURS
Total distance = 2X
Average speed = 2X / 9X/20 = 40/9 = 4.44 km - 11 years agoHelpfull: Yes(23) No(0)
- 2*a*b/(a+b)=2*4*5/9=40/9
- 11 years agoHelpfull: Yes(4) No(0)
- 2xy/x+y so, 2*4*5/4+5=40/9
- 11 years agoHelpfull: Yes(3) No(0)
- let the distance be x km
so time t1 (for going A to B ) = x/4
and time t2 (for coming back to B from A) = x/5
average speed = (2x)/(x/4 + x/5)= 40/9 =4.44kmph - 11 years agoHelpfull: Yes(2) No(0)
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