If the equation (k^2 - 5k + 6)x^2 + (k^2 - 7k + 12)x + k^2 - 9 = 0 satisfy more than two values of x, then the value of k is
option
a) -3
b) 3
c) 2
d) 4

• Ans = 3
  any quadratic equation of power 2 satisfying more than two values of x then it might be satisfy x=0;
  putting x=0;
  k2=9
  k=+3, -3
  
  -3 is not supporting so K=3
• 11 years agoHelpfull: Yes(10) No(1)
• if the eq yields two values of x
  then b^2 - 4ac > 0
  that is done in option a only i.e. -3
• 11 years agoHelpfull: Yes(3) No(1)
• why -3 is not supporting....(-3)^2=9 also
• 11 years agoHelpfull: Yes(2) No(2)