Sum of three digit number is 17. sum of squared of digits of the given number is 109. If we subtract 495 from that number 5 we will get a number written in square order. find the number.

• Ans:863
  sum of the three digit is 17..hence a+b+c=17----(1)
  sum of squared of digits is 109 ..hence a^2+b^2+c^2=109----(2)
  Also, 100a+10b+c-495=100c+10b+a
  99(a-c)=495
  a-c=5
  The possible combinations are (6,1)(7,2)(8,3),(9,4)
  out of these combinations 8,3 oly satisfies both (1) nd (2)
  8+b+3=17
  b=6
  hence 8+6+3=17
  8^2+6^2+3^2=64+36+9=109
  so,863 is ans...
• 11 years agoHelpfull: Yes(41) No(1)
• why 100a+10b+c-495=100c+10b+a
  
• 9 years agoHelpfull: Yes(8) No(0)
• First the no which is of sum 17 of 3 digits is 386(3+8+6=17)
  whose squares sum is 109 and we subtract that num by 495 we get 109 which is of sum of square order.
• 11 years agoHelpfull: Yes(6) No(2)
• 863
  
  a+b+c=17
  a^2+b^2+c^2=109
  100a+10b+c-495=100c+10b+a
  from here
  a-c=5
  possibilities
  6-1
  8-3
  9-4
  check it only 8 and 3 satisfy the starting two equation
• 11 years agoHelpfull: Yes(5) No(0)
• Does number in square order means reverse order,i.e abc becomes cba
• 11 years agoHelpfull: Yes(5) No(0)
• @Akhilesh Agrawal Is the sqaure order means revers order coz u changed abc to cba????
• 11 years agoHelpfull: Yes(2) No(0)
• From the given information assume that xyz is a given number
  1)x+y+z=17--------eqn(1)
  2)(x^2)+(y^2)+(z^2)=109--------eqn(2)
  
  100x+10y+z-495=100z+10y+x
  100x+10y+z-495-100z-10y-x=0
  99x-99z-495=0
  99(x-z)=495
  x-z=495/99
  x-z=5
  so here x value is greater than 5 and z value is less than 5
  Among the possiblities of getting 5 8 and 3 satifies the equation
  so x=8 and z=3
  from eqn(1) y=6
  
  so the Answer is 863
  
  
• 8 years agoHelpfull: Yes(0) No(0)