Two trains each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is

• (x+2x)8=100+100=200
  
  24x=200
  x=8.3 s/m
  so answer is 2x=16.6 s/m
• 13 years agoHelpfull: Yes(26) No(6)
• speed of two train is x and 2x
  so,
  3x*8=200
  x=25/3*18/5=30
  speed of faster train is 60
• 13 years agoHelpfull: Yes(17) No(0)
• total distance=100+100=200
  speed of first train=x,speed of second train=2x
  relative speed=3x,time=200/3x
  8=200/3x,x=200/24=8.33m/s,speed of faster train=2*8.33=16.66m/s
• 13 years agoHelpfull: Yes(5) No(5)
• let speed of slow train=x and fast train =2x
  then,
  x*8+2x*8=100
  
  thus,speed os faster train=8.33 mps
• 13 years agoHelpfull: Yes(4) No(5)
• distance=2*100=200m
  time=8s
  speed=200/8=25m/s
  let the speed of slower train be x m/s, then the faster train speed is 2x m/s.
  therfore: speed= x+2x=3x m/s
  3x=25
  or, x=8.33 m/s. hence the speed of slower train is 8.33 m/s
• 13 years agoHelpfull: Yes(4) No(4)
• a train need to cross 100m with respect to each odr and that too in 8sec....so speed=12.5m/sec
  since one speed is twice that of other..so required speed of the train in 25m/sec
• 13 years agoHelpfull: Yes(3) No(8)
• time=length of both d train/speeds of the train.(s1+s2(since dey r towards each other)....hence..8=200/x+2x..x=200/24=8.33333
• 13 years agoHelpfull: Yes(2) No(6)