Find the last two digits of 2025^2052+1392^1329

• Ans is 37 .
  1392^1329-------> 2^1329 or (2^10)^132 *2^9 or 76*12=12
  and 1st part --->last 2 digit is 25
  so ans 25+12=37
  thanx :)
• 11 years agoHelpfull: Yes(15) No(10)
• first part is 25 always
  second part is 72
  thus total is 97
• 11 years agoHelpfull: Yes(10) No(1)
• 1st part is always 25.
  2nd part implies
  23^1329*2^2658 implies
  23*(23^4)^332*2^8*(2^10)^265 implies
  23*41^332*256* 24^265 implies
  23*81*256*24 implies 72
  nd 25 + 72=97..
• 11 years agoHelpfull: Yes(7) No(3)
• 25+32=57 ans
• 11 years agoHelpfull: Yes(4) No(7)
• 2025^2025+1392^1392
  25^2025+92^1392
  25+(2*2*23)^1392
  25+96
  ans=21
• 11 years agoHelpfull: Yes(2) No(7)
• give a nice logic ...
• 11 years agoHelpfull: Yes(2) No(2)
• 2025^2052 + 1392^1329
  => 25^2052 + 92^1329
  => 25 + (26 x 12)
  =>25 + 88
  =>13
  
  ans is 13.
• 11 years agoHelpfull: Yes(1) No(7)
• 2025^any digit =last digit will be 5
  1392^1329=(1392^1325)*(1392^4)=last digit will be 2
  so 2025^2052+1392^1329 =lat digit will be 7
• 11 years agoHelpfull: Yes(1) No(5)
• what is the actual logic when we have to find the any power of any no. plzzz anyone explain in detail....
• 11 years agoHelpfull: Yes(1) No(0)
• Can anybody clearly explain how 72 is obtained as the last 2 digits for 1392^1329 ??
• 11 years agoHelpfull: Yes(1) No(0)
• @Rudra:
  See if d last digit of 45^2112 is asked,the answer is 5
  Similarly if the last digit of 27^5001 is asked,yu need to do the following steps
  we know the last digit of 7*7*7*7 is "1"..i.e the last digit of 7^4 is 1. similarly last digit of 7^8=1..and so on 7^(any multiple of 4)=1;
  So we can write 27^5000 as (27^(4*1250)).here the last digit is of the result is 1.
  but we need 27^5001, so (27^(4*1250))*27. hence 1*7(last digit of 27)=7
  
  So now yu shuld be able to find the last digit of 67^5002.similarly
  
  I find it easy to find the last digit of power questions. But am not sure about the last 2 digits.!! Anybody please explain it to us. How do we find the LAST TWO DIGITS of a greater power arithmetic problem?
• 11 years agoHelpfull: Yes(1) No(0)
• 2025^2052 + 1392^1329
  => 25^2052 + 92^1329
  => 45 + (26 x 12)
  =>45 + 88
  =>33
  
  ans is 33.
• 11 years agoHelpfull: Yes(0) No(23)
• 5^anything gives 5 , similarly 2^anything gives 2
  05+02=02
• 11 years agoHelpfull: Yes(0) No(17)
• plz explain the logic of this question..
• 11 years agoHelpfull: Yes(0) No(0)
• Ans. is 97.
  as first part is 25 surely and second part is giving 72..
  so its 97.. its coming mathematically.
• 11 years agoHelpfull: Yes(0) No(0)
• plz send the correct ans explanation to this question
• 11 years agoHelpfull: Yes(0) No(0)