what are the total no of divisor of 600(including 1 And 600)

• answer is 24
  
  firstly we have to break the number in prime factors like this
  600=(2^3)(3^1)(5^2)
  now multiply all the exponents by adding 1 in each exponents
  (3+1)*(1+1)*(2+1)=>24
• 11 years agoHelpfull: Yes(31) No(4)
• Ans:26
  Divide 600 by using prime numbers.Then we get 2^3*5^2*3=(3+1)*(2+1)*(1+1)=24
  Add 600 and 1 we get=24+2=26
  
• 11 years agoHelpfull: Yes(2) No(16)
• 24 is correct answer
  manoj is correct
  
  
• 10 years agoHelpfull: Yes(2) No(4)
• if N=a^p * b^q * c^r then the no. of factor of N=(p+1)(q+1)(r+1)
  600=2^3 *3^1 * 5^2
  so,the no of factor of 600=(3+1)(1+1)(2+1)=24 ans.
• 9 years agoHelpfull: Yes(2) No(1)
• total 600=2^3*3^1*5^2
  hence total no of divisors are:- (3+1)(1+1)(2+1)
  =4*2*3=24
• 9 years agoHelpfull: Yes(1) No(0)
• factors of 600=(2^3)*(3^1)*(5^2)
  so sum of factors=((3+1)*(1+1)*(2+1))=24
  since 1 and 600 is included..so total no of divisor=24+1=25
• 11 years agoHelpfull: Yes(0) No(10)
• 24 is the correct answer
• 9 years agoHelpfull: Yes(0) No(0)
• The answer is 24.
• 8 years agoHelpfull: Yes(0) No(0)