the average of five number is 27 if one number is excluded the average becomes 25 the excluded number is

• sum of five numbers/5=27 so sum = 135 then sum of 4 numbers/4 = 25 so sum= 100 135-100 = 35
• 11 years agoHelpfull: Yes(0) No(0)
• let a+b+c+d+e/5=27 hence a+b+c+d+e=135
  then one number is excluded ,a+b+c+d/4=25 hence a+b+c+d=100
  135-100=35..
  ANS:35
• 11 years agoHelpfull: Yes(0) No(0)
• Reduced value is 27-25=2 That is....
  The reduced value 2 is reduced from each five no. so 5*2=10
  Now add 10 with 25 we get 35. so the excluded no. is 35.
  (OR)
  (5*27-X)/4 =25
  135-X=100
  35=X
  Here X is the excluded no. Ans=35
• 11 years agoHelpfull: Yes(0) No(0)
• a+b+c+d+e/5=27
  a+b+c+d+e=135
  then,a+b+c+d/4=25
  a+b+c+d=100
  then,(a+b+c+d+e)-(a+b+c+d)=135-100=35
  ans is 35
• 11 years agoHelpfull: Yes(0) No(0)
• answer is 35
• 11 years agoHelpfull: Yes(0) No(0)
• sum of five nos=27*5=135;
  sum of four nos=25*4=100;
  so,excluded no=135-100=35
• 11 years agoHelpfull: Yes(0) No(0)
• sum of 5 nos.=27*5=135
  since, 1 no. is excluded,avg becomes 25
  then,sum of 4 nos=25*4=100
  hence,excluded no.=(sum of 5 nos-sum of 4 nos.)=(135-100)
  35
  
• 11 years agoHelpfull: Yes(0) No(0)