The matrix of a(7,9) was given.the address of the first byte of a(1,1)=1258.it takes 4 bytes to store the nuymber.then calculate the address of the last byte of a(5,8)

• 1430 i.e. 1258+(3*36+2*32)=1430
• 11 years agoHelpfull: Yes(11) No(1)
• 1430.
  a=1258
  d=4
  n=44
  so nth term=1258+(44-1)*4=1430.
• 11 years agoHelpfull: Yes(11) No(1)
• 1434 is the answer..we have to calaculate the address of a(5,8)
  i.e from a(1,1)+a(2,2)+------a(1,9) i.e 9 terms
  a(2,1)+-------------a(2,9) i.e 9 terms
  a(3,1)+-------------a(3,9) 9 terms
  a(4,1)+-------------a(4,9) 9 terms
  a(5,1)-------------upto a(5,8) 8 terms
  so total 44 terms..so address calaculation is given by
  starting address+(no. of terms)(no. of bytes)=1258+44(4)=1434
• 11 years agoHelpfull: Yes(11) No(4)
• 1434... (4*36)+(4*8) =176..add it with 1258+176=1434.
• 11 years agoHelpfull: Yes(3) No(5)
• 1430 is correct
• 11 years agoHelpfull: Yes(2) No(0)
• number will be start storing from 1430 but question has asked abt the last byt of storage, so after storing (5.8),last byt will be 1434.
  address calculation formula= base address+ no.of col * (no. of rows-1)*size of storing 1 number + (no. of col - 1)* size of storing 1 no.
  1258+ 9*(5-1)*4+(8-1)*4=1430,
  but last byt will be at 1434.
• 11 years agoHelpfull: Yes(2) No(0)
• 1434 is correct answer.
• 11 years agoHelpfull: Yes(1) No(3)
• Plzzzz anybody explain in details...........
• 11 years agoHelpfull: Yes(1) No(0)
• @aman plzzz explain in detail
• 11 years agoHelpfull: Yes(0) No(3)
• i didnt get it..plz explain it
• 11 years agoHelpfull: Yes(0) No(0)
• a(1,1)=1258 ; (given)
  we have to calculate the address of the last byte of a(5,8) ,i.e
  44th term in the given matrices have to find
  and if 1 term takes 4 bytes to store the number
  then 44th term will be 1258 + (44*4) = 1258 + 176 = 1434
• 11 years agoHelpfull: Yes(0) No(1)
• 1433....last byte
• 7 years agoHelpfull: Yes(0) No(0)