If 10 sweets are to be distributed among 6 children, the probability that a particular child gets 4 sweets is

• total number of combinations are n=10 r=6 n+r-1 c r-1.......so 15c5
  first give 4 sweets to that child s0 remaining n=6 as question mentioned that child should get only 4 sweets so remove that child so r=5 now find out combinations n+r-1cr-1 10c4 so answer is 10/143
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