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if given equation is 137+276=435,how much is 731+672=.... find the result..
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- 137+276=435,how it comes means 7+6=13 but in hundreth place 5 is there
so 13-8=5.but in 13 keep a carry.then, 1+7+3=11,so 11-8=3 but in 11 keep the carry up.then,1+1+2=4 so the answer is 435.
in same way,731+672=1423
how it came means,1+2=3.then,7+3=10 but 10-8=2,keep the carry up.
1+7+6=14.but 14-8=6 but keep the carry up.so,1 will come atlast
so answer is 1623
731+672=1623
- 11 years agoHelpfull: Yes(48) No(1)
- it is addition in base 8
137
+276
____
435 as in base 8, 8=10,9=11,10=12,11=13,12=14,13=15,14=16 & so on..
so 731
+672
_____
1623
- 11 years agoHelpfull: Yes(23) No(2)
- 1623 its simple addition in base 8
- 11 years agoHelpfull: Yes(19) No(10)
- its an addition of base 8
therefore,ans will be 1623 - 11 years agoHelpfull: Yes(6) No(0)
- answer 534
number are reversed in second equation - 11 years agoHelpfull: Yes(5) No(17)
- 137+276=435,how it comes means 7+6=13 but in hundreth place 5 is there
so 13-8=5.but in 13 keep a carry.then, 1+7+3=11,so 11-8=3 but in 11 keep the carry up.then,1+1+2=4 so the answer is 435.
in same way,731+672=1423
how it came means,1+2=3.then,7+3=10 but 10-8=2,keep the carry up.
1+7+6=14.
so answer atlast is 1423.
731+672=1423 - 11 years agoHelpfull: Yes(3) No(7)
- i think the ans is 534
- 11 years agoHelpfull: Yes(2) No(3)
- ans is 1480
137+276=413,but it has given 435,i.e(435-413)=22
but 2+2 is 4 which is hundred's unit of answer
so, 731+672=1403 but according to above logic hundred's digit is 14
therefore 7+7=14,which gives addition of 77 to number
so 1403+77=1480. - 11 years agoHelpfull: Yes(1) No(13)
- 731+672=534
- 11 years agoHelpfull: Yes(1) No(3)
- 1523
take base 8 and solve
- 11 years agoHelpfull: Yes(1) No(5)
- Answer will be..
534 - 11 years agoHelpfull: Yes(0) No(6)
- i thnk its 534
- 11 years agoHelpfull: Yes(0) No(3)
- the ans is 920. let the base is x.
the 137=(b^2+3b+7) and 276=(b^2+7b=6)and 435=4b^2+3b+5....equate and solve....will get b=8....substitute for expression
- 11 years agoHelpfull: Yes(0) No(1)
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