in how many ways can one or more of 6 similar perk choclates and 5 similar kitkat choclates be given away?

• a simple formula based problem:{(p+1)(q+1)}-1=={(6+1)(5+1)}-1= 41(ans.)
• 11 years agoHelpfull: Yes(38) No(1)
• No of ways of selecting perk are 7 similarly for kitkat is 6. 1 way when none is selected so,
  7*6-1=41 ans
• 11 years agoHelpfull: Yes(4) No(0)
• (6+1)*(5+1)-1=41
• 11 years agoHelpfull: Yes(3) No(1)
• She might choose to not give any kitkats. So her ways of giving Kitkats are 0, 1, 2, 3, 4 i.e. 5 ways. Similarly for the others. So 5 * 6 * 4. But that includes one case where she gave away none of the three so for "1 or more" chocolates to be given we minus 1.
• 11 years agoHelpfull: Yes(3) No(3)