A man sold 12 candies in 10$ had loss of b% then again sold 12 candies at 12$ had profit of b% find the value of b.

• Let the CP be 'x' then:
  (x-10)*100/x = b% ----------->1
  (12- x) * 100 /x = b% ------->2
  (x-10)*100 / x = (12-x)*100 / x
  x-10 = 12-x
  x = 11
  So by Submitting value of x into one of above question (1 or 2) we get b%
  which is 9.09 or 9 Approx
• 11 years agoHelpfull: Yes(49) No(6)
• Sry...
  the formula is:
  (100-loss%):(1stSP)=(100+gain%):(2ndSP)
  by using this ...
  the value of b will be 9
• 11 years agoHelpfull: Yes(22) No(4)
• by using
  (100-loss%):(1stSP)=(100-gain%):(2ndSP)
  (100-b):10=(100+b):12
  solving this,
  b=9
• 11 years agoHelpfull: Yes(7) No(6)
• The c.p must be equidistant from 10 and 12 by obsrvatn.so,it is 11.
  so b will be (12-11)/11=1/11
• 11 years agoHelpfull: Yes(6) No(6)
• Initially,when Loss=b%,Selling Price={(100-b)/100}*Cost Price
  =>120$={(100-b)/100}*Cost Price
  =>Cost Price=12000/100-b
  Now,When profit=b%
  Selling Price={(100+b)/100}*Cost Price
  Now putting Cost price=12000/100-b,
  we get b=9.09%
• 11 years agoHelpfull: Yes(6) No(0)
• here profit%=loss%
  so,
  ((c.p-s.p)/c.p)*100=((s.p-c.p)/c.p)*100
  =>c.p=11
  by keeping this value in profit or loss % formula we get value of b as 9.
• 11 years agoHelpfull: Yes(4) No(1)
• actual price = [10*(100+b)/100] (when 12 candies in 10$ had loss of b%)
  actual price = [12*(100-b)/100] (when 12 candies at 12$ had profit of b%)
  [10*(100+b)/100] = [12*(100-b)/100]
  =>b=100/11 => b = 9.09
  
• 11 years agoHelpfull: Yes(4) No(0)
• 120=x-b%; b=132-120=12
  144=x+b
  2x=264;
  x=cp=132
• 11 years agoHelpfull: Yes(0) No(5)
• gain=sp-cp
  gain%=gain*100/cp
  b*100/x=-x+144_________ 1
  loss=cp=sp
  b*100/x=x-120__________2
  sub 1-2 =x=cp=132
  b*100/132=12
  b=15.84
  
• 11 years agoHelpfull: Yes(0) No(12)
• c.p=10+b/10
  c.p*(100+b)%=12
  solving we get b=9.09
• 11 years agoHelpfull: Yes(0) No(0)
• 100-b corresponds to10/12 then 100+b corresponds to x=>x=6.25
• 8 years agoHelpfull: Yes(0) No(2)
• Plz equate the cost price u will find the solution
• 5 years agoHelpfull: Yes(0) No(0)