The citizens of planet Oz are 6 fingered and thus have developed a number system in base 6. A certain street in Oz contains 1000 buildings numbered from 1 to 1000. How many 3’s are used in numbering these buildings? Express your answer in base 10.

• 1 to 1000,we have 300 times 3 occurs.this is in base 6,so ans is 108.
  that 108 in base 10,
  {(1*10 to the power of 2)+(0*10 to the power of 1)+(8*10 to the power of 0)}
  so the ans is 108
• 13 years agoHelpfull: Yes(20) No(12)
• 3*x*x
  where x=base here it is 6
  3*6*6=108
• 13 years agoHelpfull: Yes(16) No(7)
• 204
  Since the number system has base 6 so only 0,1,2,3,4,5 digits are allowed.with these digits the numbers are-
  0,1,2,3,4,5,10,11,12,13,14,15,...90,91,92,93,94,95 here 3 occurs 16 times.
  again 100,101,102,103,104,105.....190,191,192,193,194,195 here also 16 times.
  for 300,301,....395....here 60 times
  
  so (16*9)+60 = 204
• 13 years agoHelpfull: Yes(3) No(35)
• Base 6 => 6^x place in number. Therefore, 1000 B 6 is in the fourth place power; but all bases start at 0 so we have actually have 1*6^3 or 216 (the preceding places are all 0*6, so there are no adders to it.
  
• 12 years agoHelpfull: Yes(1) No(3)
• The question asks "how many 3’ …" on my iPhone. I have no idea what that is. I assumed that the question is asking for a Base 10 answer???
• 12 years agoHelpfull: Yes(1) No(1)
• from (1-100) no of 3 at unit digit 3,13,23,33,43,53=6
  no 0f 3 at 10th digit 30,...,35=6
  from(101-199) no of 3 at unit digit=6
  no of 3 at 10th digit=6
  from(200-299) no of 3 at unit digit=6
  no of 3 at 10th digit=6
  from(300-399) no of 3 at unit digit=6
  no of 3 at 10th digit=6
  no of 3 at 100th digit =30
  from(400-499) no of 3 at unit digit=6
  no of 3 at 10th digit=6
  from(500-599) no of 3 at unit digit=6
  no of 3 at 10th digit=6
  total =90
  
  
• 13 years agoHelpfull: Yes(0) No(22)