Elitmus
Exam
Numerical Ability
Geometry
6 Bangles each of 4cm in daimeter,what is ther minimum diameter of plate required so that each bangles are kept without overlapping(bangles touching each other)?
Read Solution (Total 29)
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- the line joining the centre of all the circle will make a regular hexagon of side 4 cm..
according to the formula,the longest diagonal will be twice of the length of the side of the hexagon=8cm
this diagonal will be the distance between the 1st and 4th circle..
now,the circle with diameter 8 cm will pass through the center of all the circles..
minimum diameter for the plate will be 8+2+2=12 cm - 11 years agoHelpfull: Yes(82) No(8)
- one bangle at the center and the remaining 5 surrounding them.... so radius of the center + the diameter of the outer bangle....
so 4+2=6cms - 13 years agoHelpfull: Yes(54) No(62)
- the answer will be 12 cm.
- 10 years agoHelpfull: Yes(14) No(4)
- A min of 12 cm diameter plate is required because 1 in the middle and 5 around it can be arranged.
If you imagine a plate containing bangles as mentioned then we will know that the min diameter required is 12cm. - 10 years agoHelpfull: Yes(10) No(1)
- the perimeter of one bangle = pie*d = (22/7)*4
Hence, perimeter of 6 bangles = 6*(22/7)*4
now perimeter of six bangles will be equal to the perimeter of plate.
let D be the diameter of the plate
therefore, pie*D=6*(22/7)*4
or, (22/7)*D=6*22/7*4
or, D=6*4=24
Hence, diameter pf the plate will be 24cm..........It may be, not sure - 13 years agoHelpfull: Yes(6) No(43)
- anyone tell me correct answer of this question??
- 11 years agoHelpfull: Yes(5) No(2)
- it is less than 12 cm.
- 12 years agoHelpfull: Yes(4) No(4)
- the perimeter of one bangle = pie*d = (22/7)*4
Hence, perimeter of 6 bangles = 6*(22/7)*4
now perimeter of six bangles will be equal to the perimeter of plate.
let D be the diameter of the plate
therefore, pie*D=6*(22/7)*4
or, (22/7)*D=6*22/7*4
or, D=6*4=24
Hence, diameter pf the plate will be 24cm. - 12 years agoHelpfull: Yes(4) No(21)
- 1 in center and remaining 5 in surrounding. so radius will be = 4+(4/2)=6cm
and diameter of plate is=6*2= 12 cms - 10 years agoHelpfull: Yes(4) No(0)
- ans is 6...compare the sum of areas of 6 bangle(circle) with the bigger circle(plate)...
24*pi >= pi*r^2
=> r=5.xx
considering the next integer...r=6 - 11 years agoHelpfull: Yes(3) No(8)
- 1 in center and remaining 5 in surrounding. so radius will be = 4+(4/2)=6cm
and diameter of plate is=6*2= 12 cms....
- 9 years agoHelpfull: Yes(2) No(0)
- 6 bangles have to kept around a plate in such a way that they should not overlap !
lets say the min dia of the plate is R
then the circumference of that plate comes out to be - 2*pi*R
also the circumference of the plate equals 6*4
equating both the above equations we obtain =>
2*pi*R = 6*4
giving R= 3.8cm - 13 years agoHelpfull: Yes(1) No(17)
- for completely occupy the diameter of the plate which cover all the 6 bangles without overlapping we put
1 bangle center of the plate alll other 5 around that bangle hence
the min dia of the plate would be = 2+4
=6cm - 10 years agoHelpfull: Yes(1) No(0)
- diameter of plate should be 12cm
- 9 years agoHelpfull: Yes(1) No(0)
- perimeter of plate containing 6 bangles>=2*3.14*(4/2)*6
6 is multiplied becoz 6 plates are there
hence required perimeter will be >=2*3.14*R
on comparing 2*3.14*R=2*3.14*2*6
Hence,clearly minimum R=2*6=12 cm - 9 years agoHelpfull: Yes(1) No(0)
- answer will be 12
- 7 years agoHelpfull: Yes(1) No(0)
- the distance between 1st and 4th circle would be around dist = sqrt(6*6+4*4)
which is(7.21 cm) and radoius of two circles (2+2 = 4)
than overall diameter of plate would be around 7.21+4 = 11.21cm. - 12 years agoHelpfull: Yes(0) No(3)
- (4 root 3)/3 + 2
- 11 years agoHelpfull: Yes(0) No(3)
- it should be 14cm
- 10 years agoHelpfull: Yes(0) No(2)
- correct ans is 6 cm
6*4=24,
now total dia meter is devided by diameter of one bangle dia.
24/4=6 cm - 10 years agoHelpfull: Yes(0) No(0)
- answer will be nearest 12 cm diameter (
- 9 years agoHelpfull: Yes(0) No(0)
- my ans is 11.6cm. Kindly mention options along wd d ques. so that one cn chk ans.
- 9 years agoHelpfull: Yes(0) No(0)
- One bangle in center and remaining 5 surrounding them .....and so radius of center bangle + outer bangles
so total diameter = 11.23 cm(accurate) - 9 years agoHelpfull: Yes(0) No(0)
- it is given that
S2n = 3Sn
but Sn = n(n+1)/2
=> 2n(2n+1)/2 = 3n(n+1)/2
=> n = 1
then S3n/Sn = [3n(3n+1)/2]/[n(n+1)/2] = 3*4/1*2 = 6
- 9 years agoHelpfull: Yes(0) No(0)
- One bangle at the center and the remaining 5 surrounding them, so radius of the center +the diameter of the outer bangle = 4+2=6cms
- 9 years agoHelpfull: Yes(0) No(0)
- 6 IHH LLJLL LLLL L L
- 8 years agoHelpfull: Yes(0) No(1)
- 1 in center and remaining 5 in surrounding.
radius = 4+(4/2)=6 cm
diameter of plate is=6*2= 12 cms - 7 years agoHelpfull: Yes(0) No(0)
- 12 is the correct answer
Explanation : 4*3 =12
Please approve - 7 years agoHelpfull: Yes(0) No(0)
- whether we take hexagon of 6 bangles or pentagon of 5 bangles with one in center ans will be 12.
for hexagon, distance of one vertex from the center of bigger circle = (length of one side of hexagon/2sin(180/6)) = 4
Thus, radius of bigger circle = 4+2 = 6, diameter = 12cm - 7 years agoHelpfull: Yes(0) No(0)
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