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the sum of two no is 5 and the product of the two is 14.what is the sum of their squares?
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- a+b=5
a*b=14
a^2+b^2=(a+b)^2-2*(a*b)
=5^2-2*14
=25-28
=-3 - 13 years agoHelpfull: Yes(12) No(11)
- the approach done by X22 or ABHISHEK KUMAR is appropriate according to the question but the very concept is that square of any no. can't be possible. so there may certainly be anything wrong with this question..
- 12 years agoHelpfull: Yes(4) No(0)
- a+b=5 (given)
now squaring both sides.
(a+b)^2=25
a^2+b^2+2*a*b=25
a^2+b^2=25-2*a*b
a^2+b^2=25-28 (a*b=14)(given)
a^2+b^2=-3 - 13 years agoHelpfull: Yes(2) No(3)
- let numbers be x and y
given x+y =5, xy=14
we have , (x+y)^2 =x^2 + y^2 + 2xy
substituting, 25=x^2 + y^2 + 28
so sum of suares = - 3 - 11 years agoHelpfull: Yes(1) No(0)
- a+b=5
ab=14
(a+b)^2=a^2+b^2+2ab
a^2+b^2=(a+b)^2-2ab
=25-28
=-3
ans is -3 - 10 years agoHelpfull: Yes(1) No(0)
- question asked is sum of their squares which is x^2 + y^2
given x+y=5
so x=5-y
substitute x in xy=14
(5-y)y=14
y^2-5y+14=0
y=2 and x=3
x^2+y^2=9+4= 13
answer is 13
- 10 years agoHelpfull: Yes(0) No(1)
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