If a, b, c, are three non-zero real numbers such that a + b + c = 0, and b2 ≠ ca, then the value of a2 + b2 + c2/ b2 –ca is-
Options
1) 3
2) 2
3) 0
4) 1

• As a+b+c=0, we can say that b= - (a+c)
  This means, b2= a2 + c2 +2ac
  Put this value in both numerator and denominator of the original given equation. It gives us
  a2+(a2+c2+2ac)+ c2 / (a2+c2+2ac) -ac
  
  2(a2+c2+2ac)/ (a2+c2+ac) = 2
• 8 years agoHelpfull: Yes(0) No(0)