If sin θ+ cos θ = 17/13, 0<θ<900, then the value of sin θ- cos θ is-
Options
a. 5/17

b. 3/19

c. 7/10

d. 7/13

• d)
  (sinx + cosx)² = sin²x + cos²x + 2sinxcosx = 289/169
  
  => 1 + 2sinxcosx = 289/169 => 2sinxcosx = 120/169
  
  Now,(sinx - cosx)² = 1 - 2sinxcosx = 49/169
  
  sinx - cosx = √(49/169) = ±7/13
• 7 years agoHelpfull: Yes(1) No(0)