A cylindrical rod of iron, whose height is equal to its radius, is melted and cast intospherical balls whose radius is half the radius of the rod. Find the number of balls

• 6 balls
  As volume of rod= 3.14*r^3=x
  volume of a spherical ball= (4/3)*3.14*(r/2)^3 =y
  no. of balls= x/y= 6
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