There is a 4 digit car number 4th digit is double of 1st digit 2nd n 3rd digits are same

let 1st digit be 4
then 4th digit becomes 8
since 2nd and 3rd are equal
we get 9 as a suitable no
therefore the no in the card is 4998
10 years agoHelpfull: Yes(13) No(6)

the car number is 4998
as 8 (last number) is double of 4 (1st number)
2nd and 3rd number are same which is 9
so the car number is 4998
9 years agoHelpfull: Yes(4) No(3)
ans is 1002 check for all the conditions
10 years agoHelpfull: Yes(3) No(4)
the no may be 1224,2448,4998
10 years agoHelpfull: Yes(1) No(7)
Please explain properly
10 years agoHelpfull: Yes(0) No(0)
answer is 4998
if we solve the equation from second condition then : y=(9/4)x
so x can take value either 4 or 8
since 8 is not possible as it will make the 4th digit 16 hence x will be 4.
9 years agoHelpfull: Yes(0) No(0)
its 4998. 8 is double of 4. and 98 is double of 49. there is no method of solution. its just the matter of matching the combinations & thinking.
9 years agoHelpfull: Yes(0) No(0)
Let f = the 1st digit
Then the last digit = 2f
So the number looks like: f t t 2f
Doubling the first two digits gives the last two. Treat each as a two digit number.
Then we can write this in equation form as
2(10f + t) = 10t + 2f

20f + 2t = 10t + 2f
18f = 8t
9f = 4t
t = (9/4)f
Now the number looks like: f (9/4)f (9/4)f 2f
For the digits to be integers from 0 to 9, f must equal 4. Any other value gives a non-integer digit or a digit > 9.
So the solution is 4 9 9 8
6 years agoHelpfull: Yes(0) No(0)
4998
4 digits num
8 is double of 4
2nd n 3rd digits r same
49+49=98
4 years agoHelpfull: Yes(0) No(0)

There is a 4 digit car number,
4th digit is double of 1st digit,
2nd n 3rd digits are same,
And last digits together are double of first two digits
Can you guess the car number?