There is a 4 digit car number,
4th digit is double of 1st digit,
2nd n 3rd digits are same,
And last digits together are double of first two digits
Can you guess the car number?

• let 1st digit be 4
  then 4th digit becomes 8
  since 2nd and 3rd are equal
  we get 9 as a suitable no
  therefore the no in the card is 4998
• 11 years agoHelpfull: Yes(13) No(6)
• the car number is 4998
  as 8 (last number) is double of 4 (1st number)
  2nd and 3rd number are same which is 9
  so the car number is 4998
• 10 years agoHelpfull: Yes(4) No(3)
• ans is 1002 check for all the conditions
• 11 years agoHelpfull: Yes(3) No(4)
• the no may be 1224,2448,4998
• 11 years agoHelpfull: Yes(1) No(7)
• Please explain properly
• 11 years agoHelpfull: Yes(0) No(0)
• answer is 4998
  if we solve the equation from second condition then : y=(9/4)x
  so x can take value either 4 or 8
  since 8 is not possible as it will make the 4th digit 16 hence x will be 4.
  
• 10 years agoHelpfull: Yes(0) No(0)
• its 4998. 8 is double of 4. and 98 is double of 49. there is no method of solution. its just the matter of matching the combinations & thinking.
• 9 years agoHelpfull: Yes(0) No(0)
• Let f = the 1st digit
  Then the last digit = 2f
  So the number looks like: f t t 2f
  Doubling the first two digits gives the last two. Treat each as a two digit number.
  Then we can write this in equation form as
  2(10f + t) = 10t + 2f
  
  20f + 2t = 10t + 2f
  18f = 8t
  9f = 4t
  t = (9/4)f
  Now the number looks like: f (9/4)f (9/4)f 2f
  For the digits to be integers from 0 to 9, f must equal 4. Any other value gives a non-integer digit or a digit > 9.
  So the solution is 4 9 9 8
• 7 years agoHelpfull: Yes(0) No(0)
• 4998
  4 digits num
  8 is double of 4
  2nd n 3rd digits r same
  49+49=98
• 4 years agoHelpfull: Yes(0) No(0)