Raj writes a number He sees that the number of two digits exceeds four times the sum of its digit

ANS- 13
(10X + Y)+3= 4(X+Y) ......EQUATION-1
10X + Y +18 = 10Y + X .....EQUATION-2

SOLVING ABOVE
X=1, Y=3
THEREFORE, NUMBER =13
10 years agoHelpfull: Yes(10) No(23)
10x+y=4(x+y)+3....
(10x+y)+18=10y+x....

Ans :35
10 years agoHelpfull: Yes(4) No(6)
ans-35
given that
10x+y=4(x+y)+3....eq1
(10x+y)+18=10y+x....eq2
solve this eq1 and eq2 u'll get x=3 and y=5
so its 35.
10 years agoHelpfull: Yes(3) No(3)
let the no. be (10x+y),
equation-1:- (10x+y)=4(x+y)-3
equation-2:- 10x+y+18=10y+x

on solving above equs we get x=1,y=3, there fore the ans is "13"
10 years agoHelpfull: Yes(3) No(6)
10x+y=4(x+y)+3
10x+y+18=10y+x
on solving we get x=3 n y=5
so no is 35
10 years agoHelpfull: Yes(3) No(2)
let the unit digit is y and tens digit is x
now 10x+y=4(x+y)+3 .....(1)
and 10y+x=10x+y+18 ......(2)
by solving the eq.x=3 and y=5
so the ans is 35
10 years agoHelpfull: Yes(3) No(2)
let the no. be 10x+y
then,10x+y-4(x+y)=3 [equation(1)]
also,10x+y+18=10y+x [equation(2)]
solving (1) & (2),
we get,x=3 & y=5
Hence,the no. is 35
10 years agoHelpfull: Yes(1) No(2)

Raj writes a number. He sees that the number of two digits exceeds four times the sum of its digit by 3. If the number is increased by 18, the result is the same as the number formed by reversing the digit. Find the number