the number of zeros at the end of the product 16*22*15*50*65*115*18*90 is

• 6 zeros..
  If u multiple the numbers clock only units place other than zero and count the zeros up to last product..
  
• 10 years agoHelpfull: Yes(8) No(1)
• number of zeros depend on multiplication of 5*2
  show in this equation 4 5s and 2 zeros
  so total zeros= 6
• 10 years agoHelpfull: Yes(5) No(1)
• Multiplying we get 16*15=240;22*65=1430;115*18=2060.
  Thus we get 240*50*1430*2060*90,here multiplying 240*50 we get 12000.
  Thus 12000*1430*2060*90 has 6 number of zeros at the end
• 10 years agoHelpfull: Yes(4) No(0)
• 3 zeros..
  zeros occur in these cases 2*5,4*5,6*5,8*5... so count the number of zero pairs.. and also the number of zeros..
• 10 years agoHelpfull: Yes(1) No(4)
• the number of Zeros at the end of product is 6.
  product is : 3.196908*10^12.
• 10 years agoHelpfull: Yes(1) No(0)
• 1 as all time multiply give single 0
  
• 10 years agoHelpfull: Yes(1) No(0)
• 6 zeros.
  Break each term into smaller factors and find total no. of combinations of
  5x2 .
  
• 10 years agoHelpfull: Yes(1) No(0)
• 16*15=240;22*65=1430;115*18=2070;50*90=4500.
  now,we have 24*45=1080
  so,the total no. of zeros in the end of given product is 6.
• 10 years agoHelpfull: Yes(1) No(1)
• 6 zeros
  no of zeros =2
  and no. of 5=4
  when they multiply by even then give zeroshence
  total zeros=2+4=6
  
• 10 years agoHelpfull: Yes(0) No(1)
• in each term power of 5 is calculated and 2 is calculated;
  power of 5 is 6
• 10 years agoHelpfull: Yes(0) No(0)
• 3196908000000
• 10 years agoHelpfull: Yes(0) No(1)
• no. of zeros depends on the no. of 5's and no. of 2's.
  here no. of 5's=6 and no. 0f 2's greater than 5's.
  so no. of zeros=6
• 10 years agoHelpfull: Yes(0) No(0)
• we get zero only when we make product even no with 5
  ex:2*5=10;
  in the above question no of 5s are 6.so we get 6zeros
• 10 years agoHelpfull: Yes(0) No(0)