find the remainder when 50^51^52 is divided by 11.??

a)6
b)4
c)7
d)3

• use reminder theorem. here it is given as 50^51^52. but consider it as 50*51*52 so when it is divided by 11 it gives -ve remainder of (-5)*(-4)*(-3) = 20*(-3) again use remainder theorem so now it becomes (-2)*(-3) = 6. so the ans is 6. But note that it is valid only in case of consecutive no. i.e 50,51,52 or 34,35,36 but not in case when it is given 30^72^87 etc
• 11 years agoHelpfull: Yes(44) No(4)
• answer is 6
  51^52 will give a no with unit digit 1
  50^some no with unit digit 1=((50)^some no having 0 unit digit)*50
  =some no with 0 unit digit *50
  50 divided by 11 gives 6.
• 11 years agoHelpfull: Yes(14) No(3)
• can u guys anyone please help me in getting my written test clear for tcs which is going to have my campus drive at the end of month is it enough for me to go through only tcs papers or else please help me
• 11 years agoHelpfull: Yes(11) No(0)
• pls explain this theorem
  
• 11 years agoHelpfull: Yes(3) No(0)
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• 11 years agoHelpfull: Yes(1) No(0)
• 3..using the reminder theorem
• 9 years agoHelpfull: Yes(1) No(1)
• Please Explain the Theorem
• 10 years agoHelpfull: Yes(0) No(0)