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16^100*125^135

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16^100=2^400 and
125^135=5^405 then
16^100*125^135=10^400*5^5
answer=3125*(10)^400
11 years agoHelpfull: Yes(17) No(11)

16^100=2^400
125^135=5^405
therefore,10^400*5^5
11 years agoHelpfull: Yes(4) No(0)
6^100*125^135 can also be written as

(12/2)^100*(250/2)^135
now 12 can be written as 10+2 similarly 250=248+2
pacing these we get

[(10+2)^100]/2 * [(248+2)^135]/2
by theorem of remainder we can write

2^100/2 * 2^135/2

2^99 * 2^134
adding the powers

2^233 is the answer
11 years agoHelpfull: Yes(0) No(3)

TCS Other Question

if b is the mean proportion between a and c then prove that a, c, a^2+b^2 and b^2+c^2 are in proportion? In a sequence of integers, A(n)=A(n-1)-A(n-2), where A(n) is the n th term in the sequence, n is an integer and n>=3, A(1)=1, A(2)=1. Calculate S(1000), where S(1000) is the sum of the first 1000 terms.