A husband gives 1000 coins of 1 Rupee each to his wife. She will put those coins in 10 bags Such that when the husband asks her wife any denomination of amount between 1-1000 She gives him few number of bags with out opening any of the bags. So, what no. of coins she has put in each bag.?

• 1, 2, 4, 8, 16, 32, 64, 128, 256, 489
  if husband needs upto 511 rupees her wife can give from bags contain 1,2,4...256 and for more than this one bag of 489 ruppes and rest of money can be taken from 1,2,...256 bags.
• 13 years agoHelpfull: Yes(8) No(1)
• dear friend 100 is the wrong answer.
  read the question carefully..
  No. of coins in each beg=
  
  beg 1= 1 coin (2^0)
  beg 2= 2 coin (2^1)
  beg 3= 4 coin (2^2)
  .
  .
  beg 10= 512 coin (2^9)
• 13 years agoHelpfull: Yes(6) No(2)
• the set of coins in each beg would be:
  
  1(2^0), 2(2^1), 4(2^2),.....512(2^9)
• 13 years agoHelpfull: Yes(4) No(5)
• 100 coins as an average expected ratio.
  because of equal n equitable distribution
• 13 years agoHelpfull: Yes(2) No(4)
• she will put 1 coin in 1st bag, 2 coins in 2nd bag and 4 in 3rd, 8 in 4th, 16 in 5th, 32 in 6th, 64 in 7th, 128 in 8th, 256 in 9th and 512 coins in 10th bag. this will help the wife to give any denomination to his husband by giving some bags. you can try yourself by taking any number.
• 13 years agoHelpfull: Yes(2) No(4)
• In Ith bag, she has to be 2 power (i-1) coins where i not equal to 10, in 10th bag, she puts all remaining coins.
• 6 years agoHelpfull: Yes(0) No(0)