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If f(x) = -ex - 2, then the range of f is given by the interval??
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If the graph of y = (x - 2)2 - 3 is translated 5 units up and 2 units to the right, then the equation of the graph obtained is given by
A. y = x^2 + 2
B. y = (x-2)^2 + 5
C. y = (x+2)^2 + 2
D. y = (x-4)^2 + 2
If f(x) = (x - 1) / (x^2 - 9), then the domain of f is given by the interval
A. (1 , +)
B. (-3 , +3)
C. [1 , 3)U(3 , +)
D. (-3 , 3)U(3 , +)