there are 18 horses..winning prob of 1st horse is 1/6,2nd=1/6 and 3rd is 1/7.. no possibility of
tie.. find the chances that one of these will win the race.

• (1/6*5/6*6/7)+(5/6*1/6*6/7)+(5/6*5/6*6/7)=85/252
• 10 years agoHelpfull: Yes(16) No(3)
• answer is 10/21
• 10 years agoHelpfull: Yes(13) No(2)
• see lets take
  P(a)=1/6 P(b)=1/6 P(3)=1/7
  P(a')=1-1/6=5/6 P(b')=1-1/6=5/6 p(3')=1-1/7=6/7
  now p(1)p(2')p(3')+p(1')P(2)P(3')+p(1')p(2')p(3)
  sub u will get the ans...
• 10 years agoHelpfull: Yes(3) No(1)
• ans- 85/252
• 10 years agoHelpfull: Yes(2) No(3)
• probability=winning prob of 1st horse OR winning prob of 2nd horse OR winning prob of 3rd horse;
  =1/6+1/6+1/7;
  =10/21
• 10 years agoHelpfull: Yes(2) No(0)
• pradeep kindly explain ur ans,
  n also dat wont the presence of 18 horses affect the ans???
• 10 years agoHelpfull: Yes(2) No(0)
• kindly explain
• 10 years agoHelpfull: Yes(0) No(0)
• (1/6*5/6*6/7)+(5/6*1/6*6/7)+(5/6*5/6*6/7)=210/252=5/6...
  
• 10 years agoHelpfull: Yes(0) No(0)
• plz explain
• 8 years agoHelpfull: Yes(0) No(0)